大家好，最近要做一个在ARM上用到gmp库的东西，所以要交叉编译gmp.有一个网站上找到了编译方法。可是我编译的时候老是报错，当我：
./configure CC="/opt/arm/usr/bin/arm-linux-gcc" CPP="/opt/arm/usr/bin/arm-linux-gcc  -E"   报错如下：
[root@localhost gmp-4.3.2]# ./configure CC="/opt/arm/usr/bin/arm-linux-gcc"
CPP="/opt/arm/usr/bin/arm-linux-gcc -E"
checking build system type... i686-pc-linux-gnu
checking host system type... i686-pc-linux-gnu
checking for a BSD-compatible install... /usr/bin/install -c
checking whether build environment is sane... yes
checking for gawk... gawk
checking whether make sets $(MAKE)... yes
checking whether to enable maintainer-specific portions of Makefiles... no
checking ABI=32
checking whether /opt/arm/usr/bin/arm-linux-gcc is gcc... yes
checking compiler /opt/arm/usr/bin/arm-linux-gcc -m32 -O2 -pedantic
-fomit-frame-pointer ... no
checking compiler /opt/arm/usr/bin/arm-linux-gcc -O2 -pedantic
-fomit-frame-pointer ... no, program does not run
configure: error: could not find a working compiler, see config.log for
details
[root@localhost gmp-4.3.2]#

求大家指点一下吧！

正确交叉编译gmp的方法是(以6410为目标平台)
export PATH=/opt/arm/usr/bin:$PATH
$CFLAGS="-march=armv6" ./configure --host=arm-linux
$make

引用第1楼kasim于2012-05-22 15:43发表的  :
正确交叉编译gmp的方法是(以6410为目标平台)
export PATH=/opt/arm/usr/bin:$PATH
$CFLAGS="-march=armv6" ./configure --host=arm-linux
$make

多谢，可是第二条语句我不太懂！

对于执行configure脚本而言，设定CFLAGS环境变量为"-march=armv6", 这其实是arm-linux-gcc的执行参数，用来确保生成的二进制档是适用于armv6平台的，比如S3C6410